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<p>Hi,Will<br>
Thanks<br>
<tt><br>
>> Hi,<br>
>> This is a question about the different of memory size between lpar and HMC. </tt><br>
<tt>>>...<br>
<br>
>> 2. In lpar didolp2: We get the size of memory is 2174672KB.<br>
>> [root@didolp2 ~]# cat /proc/meminfo<br>
>> MemTotal: 2174672 kB<br>
>><br>
>> The question is: 2174672/(32*1024) = 66.36572265625<br>
<br>
>MemTotal is the amount of free memory in the partition, which does not<br>
>include the memory that holds the kernel code, (bss, data, init).<br>
<br>
>There should be a few other pieces of data that will add up to the numbers<br>
>you are looking for.<br>
<br>
>in early boot messages, there is a line "SystemCfg->physicalMemorySize =<br>
>0x.......". This value should be precisely what you are trying to<br>
>measure.<br>
<br>
>A bit later in the logs, you can also see a line<br>
>"Memory: XXXXk/YYYYk available (###k kernel code, ###k reserved, ###k data,<br>
>###k bss, ###k init).<br>
>the YYYYk should also match what you are looking for.</tt><br>
<br>
If the system boot up several days before, the boot log is not available at this time. Whether there has any other method to get the physical memory from lpar. <br>
<br>
Could the OS provide a method to obtain the real memory. It will help to dynamic reassign resource according by the load between several partition.<br>
<br>
<br>
Thanks & Best regards,<br>
<br>
--------------------------------------------<br>
Wang Zhaoyu<br>
<br>
Email: wangzyu@cn.ibm.com <br>
Notes: Zhao Yu Wang/China/Contr/IBM@IBMCN</body></html>